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21m^2-140m=-84
We move all terms to the left:
21m^2-140m-(-84)=0
We add all the numbers together, and all the variables
21m^2-140m+84=0
a = 21; b = -140; c = +84;
Δ = b2-4ac
Δ = -1402-4·21·84
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{12544}=112$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-140)-112}{2*21}=\frac{28}{42} =2/3 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-140)+112}{2*21}=\frac{252}{42} =6 $
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